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十进制转K进制 - 题解
```
#include <bits/stdc++.h>
#define endl '\n'
using namespace std;
typedef pair<int,int> aII;
using ll = long long;
using ULL = unsigned long long;
const int N = 1e6+5;
ll res, m;
string ans;
inline void solve() {
cin >> res >> m;
while (res) {
auto x = res % m;
if (x >= 10 && x <= 15) ans += x + 'A' - 10;
else ans += x + '0';
res /= m;
}
reverse(ans.begin(),ans.end());
cout << ans << endl;
}
int main() {
ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int _ = 1;
//int _; cin >> _;
while (_--) solve();
return 0;
}
```
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十进制转K进制 - 题解
```cpp
// https://dashoj.com/p/95
#include <bits/stdc++.h>
using namespace std;
int s, base;
int main() {
cin >> s >> base;
char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
string result;
while (s != 0) {
result.push_back(digits[s % base]);
s /= base;
}
reverse(result.begin(), result.end());
cout << result << endl;
return 0;
}
```
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十进制转K进制 - 题解
``
```
#include
using namespace std;
int s,base;
string p="0123456789ABCDEF";
string ans;
int main()
{
cin>>s>>base;
while(s){
ans.push_back(p[s%base]);
s/=base;
}
reverse(ans.begin(),ans.end());
cout<<ans;
return 0;
}
```
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