题解分享
题解分享简介
判断能否被3,5,7整除 - 题解
```
// 1. 用if分支判断
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin >> n;
if ( n % 3 == 0 && n % 5 == 0 && n % 7 == 0 ) {
cout << "3 5 7";
}
else if ( n % 3 == 0 && n % 5 == 0 ) {
cout << "3 5";
}
else if ( n % 5 == 0 && n % 7 ==0 ) {
cout << "5 7";
}
else if ( n % 3 == 0 && n % 7 == 0) {
cout << "3 7";
}
else if ( n % 3 == 0 ) {
cout << "3";
}
else if ( n % 5 == 0 ) {
cout << "5";
}
else if ( n % 7 == 0 ) {
cout << "7";
}
else {
cout << "n";
}
return 0;
}
```
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