题解分享
题解分享简介
奇偶数判断 - 题解
```
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin >> n;
if ( n % 2 == 0 ) {
cout << "even";
} else {
cout << "odd";
}
return 0;
}
```
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