题解分享
题解分享简介
计算2的幂 - 题解
```
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin >> n;
long long sum = 1;
for ( int i = 1; i <= n; i++ ) {
sum = sum * 2;
}
cout << sum;
return 0;
}
```
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