我这个代码在洛谷和c语言网都只有78分, 但是在这里可以AC😄 , 我乱写的代码.... 什么混分中, 正解看不懂 ```cpp #include <cstdio> #include <vector> #include <algorithm> #include <set> using namespace std; using ll = long long; int main() { int n; scanf("%d", &n); vector<ll> arr; set<ll> tmp_set; for (int i = 0; i < n; ++i) { ll j; scanf("%lld", &j); tmp_set.insert(j); } for (ll it : tmp_set) { arr.push_back(it); } // 16 -1.5 (*3 / 2)-> -1.5 (*3 / 2)--> 36 -1.5 (*3 / 2)--> 54 // a b c // b = q*a, c = p*b // 公比 = p, q 的 最小公约数 // p = 36 / 16 = 3 // q = 54 / 36 = 1.5 double q = 1e18; // 32 ->*6-> 200 ->15-> 3125 15/6 -> 5/2 // 2 ->*262,144-> 524288 -> *1,048,576 -> 549755813888 1,048,576/262,144 = 4/1 double p = 0; for (int i = 1; i < arr.size(); ++i) { double tmp = (double)arr[i] / arr[i - 1]; q = min(q, tmp); p = max(p, tmp); } double res = p / q; if (res == 1.0) { ll gy = __gcd(arr[1], arr[0]); printf("%lld/%lld\n", arr[1] / gy, arr[0] / gy); } else { ll fm = 1, fz; while (res - (ll)res >= 1e-6) { res *= 10; fm *= 10; } fz = res; ll gy = __gcd(fz, fm); if (fz / gy) printf("%lld/%lld\n", fz / gy, fm / gy); else printf("0/0\n"); } /* 2 -> *262,144-> 524288 -> *1,048,576 -> 549755813888 *2 -> x 1,048,576/262,144 = 4/1 4 16 24 36 54 3 16 36 54 6 2 32 8 16 32 128 */ return 0; } ```