更难的都不会做了只能做简单的 #include <bits/stdc++.h>

using namespace std;

using ll =long long;

//ll gcd (ll a, ll b){ // return b==0 ? a: gcd(b, a%b); // //} int main() { ll a ,b; cin >>a>>b; cout << a/ __gcd( a, b) *b;//使用 c++自带的方法 __gcb

}

// https://dashoj.com/p/93
#include <bits/stdc++.h>

using namespace std;
typedef long long ll;

ll gcd(ll a, ll b) {
	if(b == 0) return a;
	return gcd(b, a % b);
}

ll lcm(ll a, ll b) {
	return a / gcd(a, b) * b;
}

int main() {
	ll a, b;
	cin >> a >> b;
	cout << lcm(a, b) << endl;
	return 0;
}