4 条题解

  • 0
    @ 2024-12-12 23:33:36
    #include <bits/stdc++.h>
    
    using namespace std;
    
    int i; 
    int num_even = 0;
    int num_odd = 0;
    
    int main() {
        while(cin >> i)
            if (i % 2 == 0) 
                num_even++;
            else
                num_odd += i; 
        cout << num_even << endl << num_odd << endl;
        return 0;
    }
    
    • 0
      @ 2024-4-7 11:43:02
      import java.util.Scanner;
      
      public class Main {
      public static void main(String[] args) {
      Scanner sc = new Scanner(System.in);
      int count = 0;
      int sum = 0;
      String s = sc.nextLine();
      sc.close();
      
      String[] strArray = s.split(" "); // 使用一个空白字符作为分隔符
      
      int[] intArray = new int[strArray.length];
      for (int i = 0; i < strArray.length; i++) {
      intArray[i] = Integer.parseInt(strArray[i]); // 将每个子字符串转换为整数
      }
      
      for (int i = 0; i < intArray.length; i++) {
      if (intArray[i] % 2 == 0) {
      count += 1;
      } else {
      sum += intArray[i];
      }
      }
      System.out.println(count);
      System.out.println(sum);
      
      }
      
      
      }
      
      • 0
        @ 2024-4-6 13:34:17
        //模板
        #include <bits/stdc++.h>
        using namespace std;
        #define endl '\n'
        #define INF 0x3f3f3f3f3f3f3f3f
        #define int long long
        
        signed main(){
        	ios::sync_with_stdio(0);
        	cin.tie(0);
        	cout.tie(0);
        	
        	int n , cnt = 0 , ans = 0;
        	
        	while(cin >> n)
        	{
        		if(n % 2 == 0)
        		{
        			cnt++;
        		}
        		else{
        			ans += n;
        		}
        	}
        	
        	cout << cnt << endl	<< ans ;
        	
        	return 0;
        }
        
        • 0
          @ 2024-4-5 13:41:44
          #include <iostream>
          using namespace std;
          int a,ans,n;
          int main()
          {
            ios::sync_with_stdio(0);
            cin.tie(0);
            cout.tie(0);
            while(cin>>a)
            {
              if(a==0)break;
              if(a%2==0){
                n++;
              }
              else
              ans+=a;
            }
            cout<<n<<"\n"<<ans;
            return 0;
          }
          
          • 1

          信息

          ID
          9
          时间
          1000ms
          内存
          256MiB
          难度
          3
          标签
          递交数
          929
          已通过
          473
          上传者