4 条题解
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2
#include<iostream> #include<map> #include<string> using namespace std; int main() { map<string, string> mp; string name, number; int n, m; cin >> n >> m; for (int i = 1; i <= n; i++) { cin >> name >> number; mp[name] = number; } for (int i = 1; i <= m; i++) { string x; int c; cin >> c >> x; if (c == 1) { auto it = mp.find(x); if (it != mp.end()) { cout << it->second << endl; } else cout << "NO" << endl; } else if (c == 2) { auto it = mp.lower_bound(x); if (it != mp.begin()) { --it; cout << it->second << endl; } else cout << "NO" << endl; } else if (c == 3) { auto it = mp.upper_bound(x); if (it != mp.end()) { cout << it->second << endl; } else cout << "NO" << endl; } } return 0; }
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1
#include<map> #include<utility> using namespace std; map<string,string>ma; pair<string,string>p; int main() { int m, n, a; string s,t,str; cin>>n>>m; while(n--) { cin>>s>>t; p.first = s; p.second = t; ma.insert(p); } while(m--) { cin>>a>>str; if(a==1) { if(ma.find(str)!=ma.end()) { cout<<ma[str]; } else{ cout<<"NO"; } } if(a==2) { if(str<=(ma.begin()->first)) { cout<<"NO"; } else { auto it = ma.lower_bound(str); it--; cout<<it->second; } } if(a==3) { if(str>=((--ma.end())->first)) { cout<<"NO"; } else { auto it = ma.upper_bound(str); cout<<it->second; } } cout<<endl; } }
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0
#include <bits/stdc++.h> using namespace std; map<string,string> m; int main() { int n,k; string name,tel; cin>>n>>k; for(int i=0;i<n;i++) { cin>>name>>tel; m[name]=tel; } while(k--) { int c; string x; cin>>c>>x; if(c==1){ auto it = m.find(x); if(it!=m.end()) cout<<it->second<<endl; else cout<<"NO"<<endl; }else if(c==2){ auto it = m.lower_bound(x); if(it!=m.begin()){ --it; cout<<it->second<<endl; }else cout<<"NO"<<endl; }else if(c==3){ auto it = m.upper_bound(x); if(it!=m.end()){ cout<<it->second<<endl; }else cout<<"NO"<<endl; } } return 0; }
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0
用文档中给的代码总有一个测试点TLE,故自己写了一个,成功AC。
#include <iostream> #include <algorithm> using namespace std; int main() { int n, t[1000100]; cin >> n; for (int i = 0; i < n; i++) scanf("%d", &t[i]); sort(t, t + n); printf("%d", t[0]); for (int i = 1; i < n; i++) if (t[i] != t[i - 1]) printf(" %d", t[i]); puts(""); }
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信息
- ID
- 68
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 8
- 标签
- 递交数
- 609
- 已通过
- 114
- 上传者