3 条题解
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0
本题有多个答案,python3在线测试所有答案都会不通过,因为测试答案是"无"。解题思路是暴力,因为数据不大
['abbbeedcbe', 'abbbeeeece', 'abcceeaece', 'abcceedcba', 'abcceeeeca', 'abddaedcba', 'cdebeeaece', 'cdebeedcba', 'cdebeeeeca']
class NaXin: def w1(self, s): # 传入字符串,看对应答案是否符合 ans = -1 for i in range(6): if s[i] == "b": ans = i + 1 break return ans == ord(s[0]) - ord("a") + 2 def w2(self, s): i = ord(s[1]) - ord("a") + 2 return s[i - 1] == s[i] def w3(self, s): x = "" if s[2] == "a": x = s[0] elif s[2] == "b": x = s[1] elif s[2] == "c": x = s[3] elif s[2] == "d": x = s[6] elif s[2] == "e": x = s[5] return x == s[2] def w4(self, s): x = chr(s.count("a") + ord("a")) return x == s[3] def w5(self, s): i = -(ord(s[4]) - ord("a")) + 9 return s[i] == s[4] def w6(self, s): if "a" <= s[5] < "e": return s.count("a") == s.count(chr(ord(s[5]) + 1)) else: flag = True for i in range(1, 5): if s.count("a") == s.count(chr(ord(s[5]) + i)): flag = False return flag def w7(self, s): if s[6] == "a": return s[7] == "e" elif s[6] == "b": return s[7] == "e" elif s[6] == "c": return s[7] == "a" or s[7] == "e" elif s[6] == "d": return s[7] == "c" or s[7] == "e" elif s[6] == "e": return s[7] == "e" def w8(self, s): c = s.count("a") + s.count("e") return chr(c - 2 + ord("a")) == s[7] def w9(self, s): c = s.count("b") + s.count("c") + s.count("d") z = [[2, 3, 5, 7], [1, 2, 6], [1, 4, 9], [1, 8], [5, 10]] ans = "" for i, v in enumerate(z): if c in v: ans += chr(ord("a") + i) return s[8] in ans if __name__ == '__main__': nx = NaXin() answer = "" def dg(s): global answer if len(answer) == 10: return if len(s) == 10: if (nx.w1(s) and nx.w2(s) and nx.w3(s) and nx.w4(s) and nx.w5(s) and nx.w6(s) and nx.w7(s) and nx.w8(s) and nx.w9(s)): answer = s return for i in range(5): c = chr(ord("a") + i) dg(s + c) dg("") print(answer)
- 1
信息
- ID
- 2
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 9
- 标签
- (无)
- 递交数
- 93
- 已通过
- 6
- 上传者