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纪念日(结果填空) - 题解

#include <iostream>
using namespace std;
int m[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
int time;
int main()
{
	int a = 1921, b = 7, c = 23;
	int year = 2020, morth = 7, day = 1;
	for (int i = 1; ; i ++ )
	{	
		c ++ ;
		if ((a % 4 == 0 && a % 100 != 0) || (a % 400 == 0))
		{
			m[2] = 29;
			if (c == m[b] + 1)
			{
				b ++ ;
				c = 1;
				
			}
		}
		else
		{
			m[2] = 28;
			if (c == m[b] + 1)
			{
				b ++ ;
				c = 1;
				
			}			
		}
		if (b == 13)
		{
			a ++ ;
			b = 1;			
		}
		if (a == year && b == morth && c == day)
		{
			cout << i * 24 * 60;
			break;
		}
	}
	return 0;
}
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