num = int(input())
count = 0
def check(n):  # 定义一个判断数字是否含有2和4的函数
    a = str(n)
    flag = False
    for i in a:
        if i == '2' or i == '4':
            flag = True
            break
    return flag


for i in range(1, num):  # 二重循环，三个数分别为i，j，num-i-j
    if check(i):
        continue
    for j in range(1, num - i):
        if check(j) or check(num - i - j) or i == j or i == num - i - j or j == num - i - j:
            continue
        else:
            count = count + 1
            continue
count = count / 6  # 得到的结果有重复的，有3！种重复，除6得到不重复的结果
print(count)