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冶炼金属(编程题) - 题解

``

#include<bits/stdc++.h> 
using namespace std;
int n,a,b;
int minn=0,maxn=1e9;
int main(){
cin>>n;
while(n--)
{
cin>>a>>b;
minn=max(minn,(int)floor(a/(b+1))+1);
maxn=min(maxn,(int)floor(a/b));


cout<<minn<<" "<<maxn<<endl;


return 0;


}

``
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