DFS
#include <iostream>
using namespace std;
const int N = 1010;
char s[] = "tencent";
int n, m;
char d[N][N];
bool st[N][N];
int ans;
int dx[] = { -1, 0, 1, 0 };
int dy[] = { 0, -1, 0, 1 };
void dfs(int x, int y, int u)
{
if (u == 6)
{
ans++;
return;
}
for (int i = 0; i < 4; i++)
{
int nx = x + dx[i], ny = y + dy[i];
if (nx >= 1 && nx <= n && ny >= 1 && ny <= m && d[nx][ny] == s[u + 1])
dfs(nx, ny, u + 1);
}
}
void solve()
{
cin >> n >> m;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++)
cin >> d[i][j];
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++)
if (d[i][j] == 't')
dfs(i, j, 0);
cout << ans << endl;
}
int main()
{
solve();
return 0;
}
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