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蛇形填数2 - 题解

#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;

const int N = 110;
int dx[4] = {-1, 0, 1, 0}, dy[4] = {0, 1, 0, -1};
int g[N][N];
int n, m;

int main()
{
    cin >> n >> m;
    int d = 2, x = 0, y = m - 1;
    for (int i = 1; i <= n * m; i ++ )
    {
        g[x][y] = i;
        int a = x + dx[d], b = y + dy[d];
        if(a < 0 || a >= n || b < 0 || b >= m || g[a][b])
        {
            d = (d + 1) % 4;
            a = x + dx[d], b = y + dy[d];
        }
        x = a, y = b;
    }
    for (int i = 0; i < n; i ++ )
    {
        for (int j = 0; j < m; j ++ )
            printf("%5d", g[i][j]);
        cout << endl;
    }
        
    return 0;
}
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