本题有多个答案，python3在线测试所有答案都会不通过，因为测试答案是"无"。解题思路是暴力，因为数据不大

['abbbeedcbe', 'abbbeeeece', 'abcceeaece', 'abcceedcba', 'abcceeeeca', 'abddaedcba', 'cdebeeaece', 'cdebeedcba', 'cdebeeeeca']

---

class NaXin:
    def w1(self, s):  # 传入字符串，看对应答案是否符合
        ans = -1
        for i in range(6):
            if s[i] == "b":
                ans = i + 1
                break
        return ans == ord(s[0]) - ord("a") + 2

    def w2(self, s):
        i = ord(s[1]) - ord("a") + 2
        return s[i - 1] == s[i]

    def w3(self, s):
        x = ""
        if s[2] == "a":
            x = s[0]
        elif s[2] == "b":
            x = s[1]
        elif s[2] == "c":
            x = s[3]
        elif s[2] == "d":
            x = s[6]
        elif s[2] == "e":
            x = s[5]
        return x == s[2]

    def w4(self, s):
        x = chr(s.count("a") + ord("a"))
        return x == s[3]

    def w5(self, s):
        i = -(ord(s[4]) - ord("a")) + 9
        return s[i] == s[4]

    def w6(self, s):
        if "a" <= s[5] < "e":
            return s.count("a") == s.count(chr(ord(s[5]) + 1))
        else:
            flag = True
            for i in range(1, 5):
                if s.count("a") == s.count(chr(ord(s[5]) + i)):
                   flag = False
        return flag

    def w7(self, s):
        if s[6] == "a":
            return s[7] == "e"
        elif s[6] == "b":
            return s[7] == "e"
        elif s[6] == "c":
            return s[7] == "a" or s[7] == "e"
        elif s[6] == "d":
            return s[7] == "c" or s[7] == "e"
        elif s[6] == "e":
            return s[7] == "e"
    def w8(self, s):
        c = s.count("a") + s.count("e")
        return chr(c - 2 + ord("a")) == s[7]

    def w9(self, s):
        c = s.count("b") + s.count("c") + s.count("d")
        z = [[2, 3, 5, 7], [1, 2, 6], [1, 4, 9], [1, 8], [5, 10]]
        ans = ""
        for i, v in enumerate(z):
            if c in v:
                ans += chr(ord("a") + i)
        return s[8] in ans

if __name__ == '__main__':
    nx = NaXin()
    answer = ""
    def dg(s):
        global answer
        if len(answer) == 10:
            return
        if len(s) == 10:
            if (nx.w1(s) and nx.w2(s) and nx.w3(s) and nx.w4(s) and nx.w5(s) and nx.w6(s) and nx.w7(s) and nx.w8(s) and nx.w9(s)):
                answer = s
            return
        for i in range(5):
            c = chr(ord("a") + i)
            dg(s + c)

    dg("")
    print(answer)