7 条题解

  • 0
    @ 2024-4-18 20:09:49
    #include <iostream>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    
    const int N = 110;
    int dx[4] = {-1, 0, 1, 0}, dy[4] = {0, 1, 0, -1};
    int g[N][N];
    int n, m;
    
    int main()
    {
        cin >> n >> m;
        int d = 2, x = 0, y = m - 1;
        for (int i = 1; i <= n * m; i ++ )
        {
            g[x][y] = i;
            int a = x + dx[d], b = y + dy[d];
            if(a < 0 || a >= n || b < 0 || b >= m || g[a][b])
            {
                d = (d + 1) % 4;
                a = x + dx[d], b = y + dy[d];
            }
            x = a, y = b;
        }
        for (int i = 0; i < n; i ++ )
        {
            for (int j = 0; j < m; j ++ )
                printf("%5d", g[i][j]);
            cout << endl;
        }
            
        return 0;
    }
    

    信息

    ID
    78
    时间
    1000ms
    内存
    256MiB
    难度
    7
    标签
    递交数
    682
    已通过
    175
    上传者