#include<cstdio>
#include<iostream>
using namespace std;
const int N=1e5+0;
int a[N];

int main(){
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	int n,num;
	cin>>n;
	long long sumb=0,sumc=0;

	for(int j=0;j<n;++j) cin>>a[j];
	for(int j=0;j<n;++j){
		cin>>num;
		sumb+=a[j]*num;
	}
	for(int j=0;j<n;++j){
		cin>>num;
		sumc+=a[j]*num;
	}
	if(sumb>sumc) cout<<"ke";
	else if(sumb==sumc) cout<<"same";
	else cout<<"do";
	return 0;
	
}

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int N;
    cin >> N;
    vector<int> score(N);
    for(int i=0; i<N; i++)
        cin >> score[i];
    vector<int> sum(2,0);
    int rate;
    for(int i=0; i<2; i++)
        for(int j=0; j<N; j++)
        {
            cin >> rate;
            sum[i]+=score[j]*rate;//题目数据给的太仁慈了
        }
    if(sum[0]>sum[1])cout << "ke" << endl;
    else if (sum[0]<sum[1])cout << "do" << endl;
    else cout << "same" << endl;
    return 0;
}

#include <bits/stdc++.h>

using namespace std;

int main() {
    int n;
    cin >> n;
    int a[3][n];

    for (int i = 0; i < 3; ++i) {
        for (int j = 0; j < n; ++j) {
            cin >> a[i][j];
        }
    }
    
    int tt = 0, xm = 0;
    for (int i = 0; i < n; ++i) {
        tt += a[0][i] * a[1][i];
        xm += a[0][i] * a[2][i];
    }

    if (tt > xm) {
        cout << "ke";
    } else if (tt == xm) {
        cout << "same";
    } else {
        cout << "do";
    }
}

#include<bits/stdc++.h>
using namespace std;
double tt_total=0,xm_total=0;
int n;
vector<int >score;
vector<double>tt_p;
vector<double>xm_p;
int main()
{
	cin>>n;
	for(int i=0;i<n;i++)
	{
		double x;
		cin>>x;
		score.push_back(x);
	}
	for(int i=0;i<n;i++)
	{
		double x;
		cin>>x;
		tt_p.push_back(x);
	}
	for(int i=0;i<n;i++)
	{
		double x;
		cin>>x;
		xm_p.push_back(x);
	}
	for(int i=0;i<n;i++)
	{
		tt_total+=score[i]*1.0*(tt_p[i]*1.0/100);
		xm_total+=score[i]*1.0*(xm_p[i]*1.0/100);
	}
	double eps=1e-6;//精度默认定义为1e-6，当fabs（x-y）<eps时，认为x==y。 
	if(fabs(tt_total-xm_total)<eps)cout<<"same";//fabs（x）：计算x的绝对值 
	else if(tt_total>xm_total)cout<<"ke";
	else cout<<"do";
	
	return 0;
 }